tìm x để \(\frac{13}{x-5}\)là 1 số nguyên
\(\Rightarrow\left(x-5\right)l\alpha.uoc.cua.13.\left(1;13\right)\)
\(\Rightarrow\hept{\begin{cases}x-5=1\\x-5=13\end{cases}}\hept{\begin{cases}x=5\\x=18\end{cases}}\)
tim so nguyen x de cac phan so sau la so nguyen 13/x-1
Tim so nguyen x de A la so nguyen, biet: A=13:(x-2)
tim cac so nguyen de tong sau la so nguyen:
a, x+1/x+3+x+12/x+13
tim cac so nguyen x de ( A=x+4/x-2)+(2x+5/x-2) la 1 so nguyen
tim so nguyen x de cac phan so sau la so nguyen a) 13:x-1 b)x+3:x-2 c) 2.x:x+2
cho bieu thuc M 3x-4
x-4
a) tim so nguyen x de m la mot so nguyen
b)tim so nguyen x de m la 1 phan so
tim so nguyen x de 2n+1/x-3 co gia tri la 1 so nguyen
tim so nguyen x de phan so sau la so nguyen x+3/x-2
Tim x nguyen de phan so sau la so nguyen
4x-1/3-x
