Question

Tìm x (. là nhân,^ là ngũ nhé)

D, (2x+1)^3+1^40=7.2^2

E,(7x—2x)^2—1^3=2^3+3^3

F,(154—2x):x=12

Giúp mk nhé !cảm ơn nhiều<3

Answer 1

\(\left(2x+1\right)^3+1^{40}=7\cdot2^2\)

\(\left(2x+1\right)^3=27\)

\(2x=2\)

\(x=1\)

\(\left(7x-2x\right)^2-1^3=2^3+3^3\)

\(\left(5x\right)^2=36\)

Th1:

\(5x=6\)

\(x=\frac{6}{5}\)

Th2:

\(5x=-6\)

\(x=-\frac{6}{5}\)

Vậy x= +- 6/5

\(\left(154-2x\right):x=12\)

\(14x=154\)

\(x=11\)