2x + 5 = x – 1 + (x + 3) – (x – 3).
2x+5=x-1+x+3-x+3
2x+5=x+5
<=>2x+5-x-5=0
<=>x+0=0
<=>x=0
Vậy x=0
2x + 5 = x - 1 + (x + 3) - (x - 3)
<=> 2x + 5 = x - 1 + x + 3 - x + 3
<=> 2x - x - x + x = -5 -1 + 3 + 3
<=> x = 0
Vậy x = 0
Bài làm
2x + 5 = x - 1 + ( x + 3 ) - ( x - 3 )
2x + 5 = x - 1 + x + 3 - x + 3
2x - x - x + x = 3 + 3 - 1 - 5
x = 0
Vậy x = 0
2x+5=x-1+(x+3)-(x-3)
\(\Rightarrow2x+5=x-1+x+3-x+3\)
\(\Rightarrow2x+5=x+5\)
\(\Rightarrow2x-x=5-5\)
\(\Rightarrow x=0\)
Vậy x=0
Chúc bn học tốt
2x+5=x-1+(x+3)-(x-3)
<=> 2x+5=x-1+x+3-x+3
<=> 2x+5=x+5
<=> 2x+5-x-5=0
<=> 3x=0
<=> x=0
Vậy x=0
2x + 5 = x - 1 + ( x + 3 ) - ( x - 3 )
=> 2x + 5 = x - 1 + x + 3 - x + 3
=> 2x + 5 = x + 5
=> 2x + 5 -x - 5 = 0
=> 3x = 0
=> x = 0
Vậy x = 0