Question

tìm x hằng đẳng thức (x-1)^2-25=0

Answer 1

`(x-1)^2-25=0`

`<=>(x-1-5)(x-1+5)=0`

`<=>(x-6)(x+4)=0`

`<=>[(x-6=0),(x+4=0):}`

`<=>[(x=6),(x=-4):}`

Vậy `x=6` hoặc `x=-4`

Answer 2

Ta có: \(\left(x-1\right)^2-25=0\)

\(\Leftrightarrow\left(x-6\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)