Mình mới học lớp 6
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\(\frac{5}{2}.x-\frac{1}{3}.x+2=\frac{3}{2}\)
\(\frac{5}{2}.x-\frac{1}{3}.x=\frac{3}{2}-2\)
\(\left(\frac{5}{2}-\frac{1}{3}\right).x=-\frac{1}{2}\)
\(\frac{13}{6}.x=-\frac{1}{2}\)
\(x=-\frac{1}{2}:\frac{13}{6}\)
\(x=-\frac{3}{13}\)
\(\frac{5}{2}x-\frac{1}{3}x+2=\frac{3}{2}\)
\(\Leftrightarrow\left(\frac{5}{2}-\frac{1}{3}\right)x+2=\frac{3}{2}\)
\(\frac{13}{6}x+2=\frac{3}{2}\)
\(\frac{13}{6}x=\frac{3}{2}-2\)
\(\frac{13}{6}x=-\frac{1}{2}\)
\(x=-\frac{1}{2}\div\frac{13}{6}\)
\(x=-\frac{3}{13}\)
Vậy \(x=-\frac{3}{13}\)