Question

Tìm x

 \(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2x\)

 

Answer 1

Theo đề bài ta có:
\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}\cdot\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2x\)
\(\Leftrightarrow\frac{4^5\cdot4}{3^5\cdot3}\cdot\frac{6^5\cdot6}{2^5\cdot2}=2x\)
\(\Leftrightarrow\frac{4^6}{3^6}\cdot\frac{6^6}{2^6}=2x\)
\(\Leftrightarrow\left(\frac{4}{3}\cdot\frac{6}{2}\right)^6=2x\)
\(\Leftrightarrow4^6=2x\)
\(\Leftrightarrow2^{12}=2x\)
\(\Rightarrow x=2^{11}=2048\)