Question

Tìm x :  \(\frac{2-x}{x+3}=\frac{6}{5}\)

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Answer 1

giúp mik với

Answer 2

\(\frac{2-x}{x+3}=\frac{6}{5}\)

<=>\(5\left(2-x\right)=6\left(x+3\right)\)

<=>\(10-5x=6x+18\)

<=>\(\left(-5x\right)-6x=18-10\)

<=>\(-11x=8\)

<=>\(x=\frac{-8}{11}\)

Answer 3

cảm ơn bn

Answer 4

gợi ý : ko có x thỏa mãn (2-x)/(x+3) = 6/5

Answer 5

ádasd
 

Answer 6

\(\frac{2-x}{x+3}=\frac{6}{5}\)

\(\Rightarrow5\left(2-x\right)=6\left(x+3\right)\)

     \(10-5x=6x+3\)

     \(-5x-6x=3-10\)

      \(-11x=-7\)

                 \(x=\frac{7}{11}\)

Answer 7

Từ đẳng thức, suy ra:

5(2-x)=6(x+3)

<=>10-5x=6x+18

<=>10-5x-6x-18=0

<=>-8-11x=0

<=>11x=-8

<=>x=-8/11

Vậy x=-8/11

Answer 8

m làm lại nha vì làm sai

\(\frac{2-x}{x+3}=\frac{6}{5}\)

\(\Rightarrow5\left(2-x\right)=6\left(x+3\right)\)

\(10-5x=6x+18\)

\(10-18=6x+5x\)

 \(-8=11x\)

 \(x=-\frac{8}{11}\)

Answer 9

\(\frac{2-x}{x+3}=\frac{6}{5}\)

\(\Leftrightarrow\left(2-x\right).5=6.\left(x+3\right)\)

\(\Leftrightarrow10-5x=6x+18\)

\(\Leftrightarrow-5x-6x=18-10\)

\(\Leftrightarrow-11x=8\Leftrightarrow x=-\frac{8}{11}\)