Ta có:
\(-\frac{3}{7}+x=\frac{1}{3}\)
=>\(x-\frac{3}{7}=\frac{1}{3}\)
=>\(x=\frac{1}{3}+\frac{3}{7}=\frac{16}{21}\)
Vậy......
-3/7+x=1/3
x=1/3--3/7
x=7/21+9/21
x=16/21
\(\frac{-3}{7}+x=\frac{1}{3}\)
\(x=\frac{1}{3}-\frac{-3}{7}\)
\(x=\frac{16}{21}\)
\(\frac{-3}{7}+x=\frac{1}{3}\)
\(x=\frac{1}{3}-\frac{-3}{7}\)
\(x=\frac{16}{21}\)