xy+2x+y=-1
<=> x(y+2)+(y+2)=1
<=> (x+1)(y+2)=1
Ta có bảng:
x+1 | 1 | -1 |
y+2 | 1 | -1 |
x | 0 | -2 |
y | -1 | -3 |
Vậy...
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xy+2x+y=-1
<=> x(y+2)+(y+2)=1
<=> (x+1)(y+2)=1
Ta có bảng:
x+1 | 1 | -1 |
y+2 | 1 | -1 |
x | 0 | -2 |
y | -1 | -3 |
Vậy...
a,tim x biet |x-2|+|3-2x|=2x+1
b,tim x,y thuoc Z biet xy+2x-y=5
c, tinh A=(1-1/15)(1-1/21)(1-1/28).....(1-1/210)
Tim X Y biet
xy-2x-y=5
Tim (x,y) nguyen biet a) x + y = x : y = xy b) 2x + 3y + 3xy = 7
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0