Ta có:
(x+2)/2012+(x+2)/2011+...+(x+2)/1996 = (x+2)/1995+(x+2)/1994+ ... + (x+ 2) / 1002
=> (x+2)(1/2012+1/2011+...+1/1996) = (x+2)(1/1995+1/1994+...+1/1002)
=> [(x+2)(1/2012+1/2011+...+1/1996)] - [(x+2)(1/1995+1/1994+...+1/1002)]=0
=> (x+2)[(1/2012+1/2011+...+1/1996)+(1/1995+1/1994+...+1/1002)]=0
=> x+2=0 (Vì (1/2012+1/2011+...+1/1996)+(1/1995+1/1994+...+1/1002) không thể bằng 0 được)
x=0-2=-2