Question

tìm x biết

x+1/-2=-8/x+1

dấu chia là phân số nhé

ai nhanh mk tick cho

Answer 1

x+1/-2=-8/x+1

=>(x+1)=(-2)(-8)=16

=>(x+1)²=4²;(-4)²

=>x=3;-5

Answer 2

Ta có: \(\frac{x+1}{-2}=\frac{-8}{x+1}\Rightarrow\left(x+1\right)^2=\left(-2\right).\left(-8\right)\)

                                            \(\Rightarrow\left(x+1\right)^2=16\)

                                             \(\Rightarrow x+1=\pm4\)

Nếu x + 1 = 4 thi x = 3

Nếu x + 1 = -4 thì x = -5

Vậy x = {-5;3}

Answer 3

Ta có \(\frac{x+1}{-2}=\frac{-8}{x+1}\)

\(\Rightarrow\left(x+1\right).\left(x+1\right)=\left(-2\right).\left(-8\right)\)

\(\Rightarrow\left(x+1\right)^2=16\)

\(\Rightarrow\left(x+1\right)^2=4^2=\left(-4\right)^2\)

\(\Rightarrow\hept{\begin{cases}x+1=4\\x+1=-4\end{cases}\Rightarrow\hept{\begin{cases}x=3\\x=-5\end{cases}}}\)

Vậy \(x\in\left\{3;-5\right\}\)

Answer 4

x+1 / -2 = -8/ x+1  ====>  (x+1).(x+1) =(-2) .(-8) = 16
 ==========> (x+1)^2 = 4^2 = -4^2
=> x+1 = 4 và x+1= -4
nếu x+1 =4 
x=3
nếu x+1=-4
x=-5
vậy x thuộc {3,-5}

Answer 5

x+1/-2=-8/x+1
=>(x+1)=(-2)(-8)=16
=>(x+1)2=42
;(-4)2
=>x=3;-5

:3

Answer 6

\(\frac{x+1}{-2}\)= \(\frac{-8}{x+1}\)

=> (x+1)(x+1)=-2.(-8)

=> (x+1)^2=16

=> x+1=4 hoặc x+1=-4

=> x =4-1 hoặc x = -4-1

=> x = 3 hoặc x = -5