giải hằng đẳng thức rồi rút gọn tìm x nhé
giải hằng đẳng thức rồi rút gọn tìm x nhé
tim x biet;(x-2)^3-x^3+6x^2=7
tim x biet;6x^2-(2x+5)(3x-2)=7
b1tifm x biet
a:(x-2)3 -x3+6x2=7 b:(3x+7)(2x-1)(6x+3)=52 c:3(x-2)2+9(x-1)-3(x2+x-3)=12
tìm xy nguyen biet (x+y-2)^2+(y+3)^2=0 tim xy thoa man x^2-6x+10=1/|x-3|+1
tim x biet x^2*(x-2)+x*(-3+2x)-5x=7
tim x biet
(2x=1)^2 - 4(x=2)^2=9
3(x-1)^2 -3x(x-5)=1
3(x+2)^2+ (2x-1)^2 =7
7(x+3)(x-3)=36
Tim x, biet
x^3+6x^2+9x-x^4=0
giup minh giai bai toan nay nhe , minh like cho
tim x,y thuoc Z biet x^2+6x=y^2
tim x biet
a/(3x-5)(2x-1)-(x+2)(6x-1)=0
b/ (3x-5)(3x+2)-(3x-1)2=-5
c/(3x+2)(x-5)=3(x-1)2-2
d/ (x+1)2/3 - (x-2)2/2 = 2x+1/2 (x-3)2/6
g/49x2=(3x+2)2
h/(3x-4)2-(2x-2)2-3(x-2)(2x-1)=0
i/ (x-2)(x2-2x+4)-x(x2+2)=15
k/ 6x2-7x-3=0
m/(x+5)(x-3)+x2-25=0
e/ x3+3x2=4x+12
f/ (6x+7)2(3x+4)(x+1)=6