\(\left(\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{97.100}\right)=\frac{0,33x}{2009}\)
\(\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{97.100}\right)=\frac{0,33x}{2009}\)
\(\left(1-\frac{1}{4}+\frac{1}{4}-...-\frac{1}{100}\right)=\frac{0,33x}{2009}\)
\(1-\frac{1}{100}=\frac{0,33x}{2009}\)
\(\frac{99}{100}=\frac{0,33x}{2009}\Rightarrow2009x99=0,33x\times100\)
198891:100:0,33=6027=x
Tìm x, biết:
a) 2x+ 2x+1 + 2x+2+ 2x+3 = 480
b) \(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+..................+\frac{1}{97.100}=\frac{0,33.x}{2009}\)
mk đang cần gấp
(\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+..........+\frac{1}{97.100}=\frac{0.33.x}{2009}\))
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+........+\frac{1}{97.100}=\frac{0.33..x}{2009}\)
giúp mik nhé
Tìm x biết : (1/1.4+1/4.7+1/7.10+....+1/97.100) = 0,33.x/2009
Tìm X <- N biết
b) ( \(\frac{11}{1.3}\)+ \(\frac{11}{3.5}\)+ ......... + \(\frac{11}{97.99}\)) . 2x = \(\frac{49}{9}\)
c) \(\frac{1}{1.4}\)+ \(\frac{1}{4.7}\)+ \(\frac{1}{7.10}\) + ........+ \(\frac{1}{97.100}\)= \(\frac{0,33.x}{2009}\)
Tìm x biết
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)
1/1.4 + 1/4.7 + 1/7.10 + ... + 1/97.100=0,33.x/2009
[1/1.4+1/4.7+1/7.10+...+1/97.100=0,33.x/2009
Tìm x
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x.\left(x+3\right)}=\frac{6}{19}\)
