pt tương đương:
[(4x+1)(3x+2)][(12x-1)(x+1)]=700
<=>(12x2+11x+2)(12x2+11x-1)=700
Đặt t=12x2+11x pt trở thành
(t+2)(t-1)=700
<=>t2+t-702=0
<=>t=26 hoặc t=-27
với t=26 =>x=13/12 hoặc x=-2
với t=-27 không có x
Giải phương trình
\(\left(x-1\right)^2-1+x^2=\left(1-x\right)\left(x+3\right)\)
\(\left(x^2-1\right)\left(x+2\right)\left(x-3\right)=\left(x-1\right)\left(x^2-4\right)\left(x+5\right)\)
\(x^4-4x^3+3x^2+4x-4=0\)
\(x^4-4x^3+12x-9=0\)
Tìm x
\(\left(4x-1\right)^3+\left(3-4x\right)\left(9+12x+16x^2\right)=\left(8x-1\right)\left(8x+1\right)-\left(3x-5\right)\)
GIÚP MIK VS
Giải phương trình
a) \(\left(6x+5\right)^2\left(3x+2\right)\left(x+1\right)=35\)
b) \(\left(4x+1\right)\left(12x-1\right)\left(3x+2\right)\left(x+1\right)-4=0\)
c) \(\left(x-1\right)\left(x-3\right)\left(x^2-4x+8\right)=6\)
d) \(\left(x-1\right)\left(x+2\right)\left(x+4\right)\left(x+7\right)=16\)
Phân tích nhân tử:
\(\left(4x-1\right)\left(12x-1\right)\left(3x+2\right)\left(x+1\right)-4\)
\(4\left(x+5\right)\left(x+6\right)\left(x+10\right)\left(x+12\right)-3x^2\)
Tìm x, biết :
a/ \(\dfrac{1}{3}x\left(x^2-4\right)=0\)
b/ \(x\left(x+5\right)=x+5\)
c/ \(x^3-\dfrac{1}{9}x=0\)
3)\(^2-\left(x+5\right)^2=0\)
e/ \(\left(x+2\right)^2-\left(x-2\right)\left(x+2\right)=0\)
f/ \(x\left(2x-3\right)-6+4x=0\)
g/ \(2\left(3x-2\right)^2-9x^2+4=0\)
h/ \(x^2\left(x+1\right)+2x\left(x+1\right)=0\)
i/ \(4x^2+9x+5=0\)
Câu 1: Rút gọn các biểu thức sau:
1. \(\left(x+y-z\right)^2+\left(y-z\right)^2+2z\left(z-y\right)\)
2. \(\left(3x+4\right)^2+\left(x-4\right)^2+2\left(3x+4\right)\left(x-4\right)\)
3.\(\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)
4. \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)\)
5. \(\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)
Câu 2: Tìm x
1. \(4\left(x+1\right)^2+\left(2x-1\right)^2-8\left(x-1\right)\left(x+1\right)=1\)
2. \(\left(3x+1\right)^2+\left(5x-2\right)^2=34\left(x+2\right)\left(x-2\right)\)
3. \(\left(x+3\right)^2+\left(x-2\right)^2=2x^2\)
4. \(4x^2-9-x\left(2x-3\right)=0\)
5. \(4x^2-12x+9=0\)
Câu 3: Tìm GTNN
D = \(\left(2x-1\right)^2+\left(x+2\right)^2\)
Câu 4: Cho \(a^2+b^2+c^2=ab+bc+ac\) . Chứng minh rằng a=b=c
Giải các PT:
a) \(\left(3x-2\right).\left(4x+5\right)=0\)
b) \(\left(2,3x-6,9\right).\left(0,1x+2\right)=0\)
c) \(\left(4x+2\right).\left(x^2+1\right)=0\)
d) \(\left(2x+7\right).\left(x-5\right).\left(5x+1\right)=0\)
BÀI 6 tìm x
1,\(2x\left(x-5\right)-\left(3x+2x^2\right)=0\) 2,\(x\left(5-2x\right)+2x\left(x-1\right)=13\)
3,\(2x^3\left(2x-3\right)-x^2\left(4x^2-6x+2\right)=0\) 4,\(5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\)
5,\(6x^2-\left(2x-3\right)\left(3x+2\right)=1\) 6,\(2x\left(1-x\right)+5=9-2x^2\)
Giải các pt sau
\(x^2+\frac{2x}{x-1}=8\)
\(\left(4x+1\right)\left(12x-1\right)\left(3x+2\right)\left(x+1\right)\)=4
\(\left(x^2-1\right)\left(x+3\right)\left(x+5\right)=9\)
\(x^4-3x^3+4x^2-6x+4=0\)
