Ta có :
\(\frac{19x+2.5^2}{14}=\left(13-8\right)^2-4^2\)
\(\Leftrightarrow\)\(\frac{19x+2.25}{14}=5^2-4^2\)
\(\Leftrightarrow\)\(\frac{19x+50}{14}=25-16\)
\(\Leftrightarrow\)\(\frac{19x+50}{14}=9\)
\(\Leftrightarrow\)\(19x+50=126\)
\(\Leftrightarrow\)\(19x=76\)
\(\Leftrightarrow\)\(x=\frac{76}{19}\)
\(\Leftrightarrow\)\(x=4\)
Vậy \(x=4\)
Tìm x biết:\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
tìm x biết : ( 19x + 2.5^2 ) : 14 = ( 13 - 8 ) ^ 2 - 4 ^2
Tìm x,biết :
a)\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
b)x+(x+1)+(x+2)+...+(x+30)=1240
c)11-(-53+x)=97
d)-(x+84)+213=-16
a) \(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
b) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
c) \(|x+7|=20+5.\left(-3\right)\)
tìm x biết :
a,5x=125
b,(19x+2.5):14=(13-8)2-42
tìm x
(19x+2.52):14-=(13-8)2-4
Tìm x biết : ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42
Tìm x:
1) \(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)
2) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
(19x+2.5^2):14=(13-8)^2-4^2
