b) (x - 2/9)3 = (2/3)6
<=> (x - 2/9)3 = 26/36
<=> (x - 2/9)3 = 64/729
<=> (x - 2/9)3 = (4/9)3
<=> x - 2/9 = 4/9
<=> x = 4/9 + 2/9
<=> x = 6/9 = 2/3
=> x = 2/3
c) (8x - 1)2x + 1 = 52x + 1
<=> (8x - 1) = 5
<=> 8x - 1 = 5
<=> 8x = 5 + 1
<=> 8x = 6
<=> x = 6/8 = 3/4
=> x = 3/4
\(b,\left(x-\frac{2}{9}\right)^3=\frac{64}{729}\)
\(x-\frac{2}{9}=\frac{4}{9}\)
\(x=\frac{2}{3}\)
\(8x-1=5\)
\(8x=6\)
\(x=\frac{3}{4}\)