a/ \(\Rightarrow\sqrt{\left(3x+1\right)^2}=1\Rightarrow3x+1=1\Rightarrow3x=0\Rightarrow x=0\)
b/ \(\Rightarrow\frac{3}{2}\sqrt{3x}-\sqrt{3x}-\frac{1}{2}\sqrt{3x}=5\)
\(\Rightarrow\sqrt{3x}\left(\frac{3}{2}-1-\frac{1}{2}\right)=5\)
\(\Rightarrow\sqrt{3x}.0=5\Rightarrow0=5\) (vô lí)
Vậy pt vô nghiệm