Các câu hỏi tương tự
Tìm x,biết:
a) \(\frac{x^7}{81}\) = 27
b) \(\frac{x^8}{9}\) 729
tìm x . biết
a)(2x+3)2=\(\frac{9}{144} \)
b) (3x-1)3=\(\frac{-8}{27}\)
c) (x4)2= \(\frac{x^{12}}{x^5}\)
d) x10=25x8
e) \(\frac{x^7}{81}\)= 27
f) \(\frac{x^8}{9}\)= 729
Xem chi tiết
a)(2x+3)2=\(\frac{9}{144} \)
b) (3x-1)3=\(\frac{-8}{27}\)
c) (x4)2= \(\frac{x^{12}}{x^5}\)
d) x10=25x8
e) \(\frac{x^7}{81}\)= 27
f) \(\frac{x^8}{9}\)= 729
tìm x biết : a,\(\frac{x^7}{81}=27\); b,\(\frac{x^8}{9}=729\); c.\(^{\left[x-\frac{1}{2}\right]^0}\); d,\(\left[X-2\right]^2=1\); e, \(\left[2X-1\right]^3=8\); f,\(\left[X+\frac{1}{2}\right]^2\)=\(\frac{1}{16}\)
Tìm X biết : x^7/81 = 27. x^8/9 = 729
1. Tìm x\(\inℚ\), biết:
a)\(\left(x-\frac{1}{2}\right)2=0\)
b)\(\left(x-2\right)^2=1\)
c) \(\left(2x-1\right)^3=-8\)
d)\(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)
e)\(\frac{x^7}{81}=27\)
g)\(\frac{x^8}{9}=^{729}\)
x^7/81 = 27
x^8/9= 729
Tìm số nguyên x ,nếu biết
\(3^x=9^{-6}.27^{-5}.81^8\)
\(2^x=8^3.8^{-10}.8^3\)
\(2^x=\frac{4^7}{8^3}\)
Bài 1: Tính: A= \(\frac{81^{10}.3^{17}}{27^{10}.9^{13}}\)
Bài 2: Tìm x, y: \(\frac{x}{7}=-\frac{12}{49}\)
Tìm x biết : \(\left(\frac{1}{3}\right)^x\left(\frac{1}{9}\right)^x\left(\frac{1}{27}\right)^x\left(\frac{1}{81}\right)^x\left(\frac{1}{243}\right)^x=\left(-\frac{1}{3}\right)^{30}\)