Question

Tìm x, biết

a)\(\frac{5}{x-2}=\frac{3}{2x+1}\)
b)

\(\frac{2x-3}{5}=\frac{x+2}{2}\)

Answer 1

\(a,\frac{5}{x-2}=\frac{3}{2x+1}\) 

=>\(5\left(2x+1\right)=3\left(x-2\right)\)

=>\(10x+5=3x-6\)

=>\(10x-3x=-6-5\)

=>\(7x=-11\)

=> \(x=-\frac{11}{7}\)

b,\(\frac{2x-3}{5}=\frac{x+2}{2}\)

=>\(2\left(2x-3\right)=5\left(x+2\right)\)

=>\(4x-6=5x+10\)

=>\(4x-5x=10+6\)

=>\(-x=16\)

=>\(x=-16\)

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Answer 2

a) 5.2x+1=x-2.3

=>10x+5=3x-6

=>10x-3x=-6-5

=>x(10-3)=-11

=>x.7=-11

=>x=\(\frac{-11}{7}\)

vậy..