Question

Tìm x, biết:

a) 8x³-x=0

b) x(x-5)=2x-10

c) 3x²+30x=-75

Answer 1

a) \(8x^3-x=0\)

\(\Leftrightarrow x\left(8x^2-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\8x^2-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=\pm\sqrt{\frac{1}{8}}\end{cases}}\)

b) \(x\left(x-5\right)=2x-10\)

\(\Leftrightarrow x\left(x-5\right)=2\left(x-5\right)\)

\(\Leftrightarrow x\left(x-5\right)-2\left(x-5\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(x-5\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x-5=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}\)

Answer 2

c) \(3x^2+30x=-75\)

\(\Leftrightarrow x^2+10x=-25\)

\(\Leftrightarrow x^2+10x+25=0\)

\(\Leftrightarrow\left(x+5\right)^2=0\)

\(\Leftrightarrow x+5=0\Leftrightarrow x=-5\)