a) \(\left(3\frac{2}{5}-2x\right).1\frac{2}{3}=5\frac{1}{7}\)
\(\left(\frac{17}{5}-2x\right).\frac{5}{3}=\frac{36}{7}\)
\(\left(\frac{17}{5}-2x\right)=\frac{36}{7}:\frac{5}{3}\)
\(\left(\frac{17}{5}-2x\right)=\frac{108}{35}\)
\(2x=\frac{17}{5}-\frac{108}{35}=\frac{11}{35}\)
\(x=\frac{11}{35}:2\)
\(x=\frac{11}{35}.\frac{1}{2}=\frac{11}{70}\)
Đúng ko z Kỳ Tỉ
Trả lời0 Đánh dấu5 giây trước (16:57)
tìm x biết
a) ($3\frac{2}{5}$325 -2x).$1\frac{2}{3}$123 =$5\frac{1}{7}$517
Toán lớp 6
a) (\(3\frac{2}{5}\) - 2x ) . \(1\frac{2}{3}\) = \(5\frac{1}{7}\)
<=> \(\frac{17}{3}\) - \(\frac{10}{3}x\) = \(5\frac{1}{7}\)
<=> \(\frac{10}{3}x\) = \(\frac{11}{21}\)
<=> \(x\) = \(\frac{11}{70}\)
b) \(\frac{x}{3}\) = \(\frac{5}{-27}\)
<=> - 27 x = 15
<=> x= \(-\frac{5}{9}\)
OK