\(a)\left(3\frac{1}{2}-x\right).1\frac{1}{4}=\frac{15}{6}\)
\(\left(\frac{7}{2}-x\right).\frac{5}{4}=\frac{15}{6}\)
\(\frac{7}{2}-x=\frac{15}{6}:\frac{5}{4}\)
\(\frac{7}{2}-x=2\)
\(x=\frac{7}{2}-2\)
\(\Rightarrow x=\frac{3}{2}\)
\(b)\frac{3}{2}-x=-\frac{7}{4}+5x\)
\(\frac{3}{2}-\frac{7}{4}=x+5x\)
\(-\frac{1}{4}=6x\)
\(x=-\frac{1}{4}:6\)
\(\Rightarrow x=-\frac{1}{24}\)
\(c)\frac{1}{2}x+150\%x=2016\)
\(\left(\frac{1}{2}+\frac{3}{2}\right).x=2016\)
\(2.x=2016\)
\(x=2016:2\)
\(\Rightarrow x=1008\)
\(d)4-\left|\frac{1}{3}-x\right|=\frac{2}{3}\)
\(\left|\frac{1}{3}-x\right|=4-\frac{2}{3}\)
\(\left|\frac{1}{3}-x\right|=\frac{10}{3}\)
\(\Leftrightarrow\frac{1}{3}-x=\pm\frac{10}{3}\)
\(\cdot\frac{1}{3}-x=\frac{10}{3}\)
\(x=\frac{1}{3}-\frac{10}{3}\)
\(x=-3\)
\(\cdot\frac{1}{3}-x=-\frac{10}{3}\)
\(x=\frac{1}{3}-\left(-\frac{10}{3}\right)\)
\(x=\frac{11}{3}\)
Vậy ta tìm được 2 giá trị x là: \(-3\)và \(\frac{11}{3}\)
