\(\left(5x+1\right)^2=\frac{36}{49}\)
\(\left(5x+1\right)^2=\left(\frac{6}{9}\right)^2\)
\(5x+1=\frac{6}{9}\)
\(5x=\frac{6}{9}-1\)
\(x=\frac{-1}{3}:5=\frac{-1}{3}.\frac{1}{5}=\frac{-1}{15}\)
tìm x biết: (5x+1)2 = 36/49
Tìm x biết:
(5x + 1)2 = 36/49
Tìm x, biết:
a) ( 5x+1)^2+36/49
b) (x-2/9)^3=(2/3)^6
c) (8x-1)^2n+1=5^2n+1
Tìm x biết
(-3/4)^3x -1= 256/81
(5x+1) ^2 =36/49
(X-2/9)^3= (2/6)^6
(8x -1)^2n+1 = 5^2n +1
Tìm x
( 5x + 1)2 = 36/49
Nhanh mk tick
Tìm x, biết:
a) 5x.(53)2=625
b) (5x+1)2=36/49
c) (8x-1)2n+1=52n=1 (n thuộc N)
Tìm x biết
a) 5x . ( 53 )2 = 625
b) ( 5x + 1 )2 =36/49
c) ( 8x - 1 )2n + 1 = 5 2n + 1
tìm x thuộc z :
\(\left(5x+1\right)^2=\frac{36}{49}\)
Tìm x,y: (5x+1)^2=36/49=(2y-1)^3
(x-2/9)^3=(2/3)^6=(y/3)^2
(8x-1)^2y+1=5^2y+1 (với y thuộc N)
