\(\frac{2x+3}{5x+2}=\frac{4x+5}{10x+2}\)
=> (2x + 3)(10x + 2) = (5x + 2)(4x + 5)
=> 20x2 + 4x + 30x + 6 = 20x2 + 25x + 8x + 10
=> 34x + 6 = 33x + 10 (bớt 2 vế đi 20x2)
=> x = 4
Tìm x biết :2x+3/5x+2 = 4x+5/10x+2
Tìm x biết: 2x+3/5x+2=4x+5/10x+2
Tìm x biết :2x+3/5x+2 = 4x+5/10x+2
tìm x biết:
2x+3/5x+2= 4x+5/10x+2
Tìm x biết:
a) (2x + 3)/(5x +2) = (4x + 5)/(10x + 2)
b) (3x - 1)/(40 - 5x) = (25 - 3x)/(5x - 34)
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
2x+3/5x+2=4x+5/10x+2.Tìm x
Tìm x, y, z biết:
a) x-y/3= x+y/3= xy/200
b) 2x+3/5x+2 = 4x+5/10x+2
Tìm x biết\(\frac{2x+3}{5x+2}=\frac{4x+5}{10x+2}\)
