1,5-3|5-2x|=12014-17/2
1,5-3|5-2x|=1-17/2
1,5-3|5-2x|=-15/2
-3|5-2x|=-15/2-3/2
-3|5-2x|=-9
|5-2x|=3
TH1:5-2x=3
2x=2
x=1
TH2:5-2x=-3
2x=8
2x=4
Vậy x=1 và x=4
Các câu hỏi tương tự
tim x,y,z biet \(\frac{3.X-5.Y}{2}=\frac{5.Y-3.Z}{3}=\frac{3.B}{4};X+Y+Z+17\)=17
Câu 1: frac{11}{12}.frac{15}{33}+frac{11}{12}.frac{2}{22}3/3frac{1}{8}.11frac{17}{19}-3frac{1}{8}.13frac{17}{19}28frac{2}{7}:left(-frac{3}{5}right)+16frac{2}{7}:left(-frac{3}{5}right)Câu 2: Tim x, y biêt4frac{1}{3}:frac{x}{4}6:0,3|2x-frac{3}{4}|-frac{1}{6}5left(x+frac{1}{3}right)^3left(frac{-1}{8}right)
Đọc tiếp
Câu 1:
\(\frac{11}{12}.\frac{15}{33}+\frac{11}{12}.\frac{2}{22}\)
\(3/3\frac{1}{8}.11\frac{17}{19}-3\frac{1}{8}.13\frac{17}{19}\)
\(28\frac{2}{7}:\left(-\frac{3}{5}\right)+16\frac{2}{7}:\left(-\frac{3}{5}\right)\)
Câu 2: Tim x, y biêt
\(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
\(|2x-\frac{3}{4}|-\frac{1}{6}=5\)
\(\left(x+\frac{1}{3}\right)^3=\left(\frac{-1}{8}\right)\)
Tim x biet
\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(\right)x+10}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
Tim x
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
2/ tim x
\(\frac{x+2015}{5}+\frac{x+2016}{6}=\frac{x+2017}{7} +\frac{x+2018}{8}\)
3/ tim x
\(\frac{1}{3}+\frac{1}{6}+\frac{99}{101}+\frac{1}{15}+... +\frac{1}{x\left(2x+1\right)}=\frac{1}{10}\)
tim x biết ( 2,5 -3x ) : 5/3=( 8/5+2x ) : -8/17
\(\left[-\frac{2}{5}x^3.\left(2x-1\right)^m+\frac{2}{5}x^{m+3}\right]:\left(-\frac{2}{5}x^3\right)\)
tim x nguyen
giai ra giup minh voi
Tim so huu ti x
a)\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\))
b)\(\frac{1}{x-1}+\frac{-2}{3}\left(\frac{3}{4}-\frac{6}{5}\right)=\frac{5}{2-2x}\)
c)\(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{2}{9-6x}-\frac{3}{2}\)
e)\(\frac{x}{2}-\frac{1}{x}=\frac{1}{12}\)
a) | x - \(\frac{1}{2}\)| + I y + \(\frac{3}{2}\)| + | 7 - \(\frac{5}{2}\)| bé hơn hoặc bằng 0
b) | 2x - 3 | + | 2x + 4 | = 7
c) | x + \(\frac{11}{17}\)+ | x + \(\frac{2}{17}\)| + | x + \(\frac{4}{17}\)| = 4x
tim cap so x,y nguyen biet :
a,\(|2x+3|+|2x-1|=\frac{8}{2|x-5|+2}\)