a) \(\sqrt{2x+\frac{5}{4}}=\frac{3}{2}\)
\(2x+\frac{5}{4}=\frac{9}{4}\)
2x = 1
\(x=\frac{1}{2}\)
b) \(\sqrt{\frac{x}{3}-\frac{7}{6}}=\frac{1}{6}\)
\(\frac{x}{3}-\frac{7}{6}=\frac{1}{36}\)
\(\frac{x}{3}=\frac{43}{36}\)
\(x=\frac{43\cdot3}{36}=\frac{129}{36}\)