Các câu hỏi tương tự
Tìm x
a \(\frac{3}{4}+\frac{1}{4}xX=2\)
b X - \(\frac{2}{3}x\frac{9}{4}=2,5-\frac{1}{2}\)
c \(2xX+\frac{1}{3}=\frac{4}{3}\)
d \(X:\frac{2}{3}+0,75=\frac{9}{4}+3\)
e \(\frac{6}{4}:X+\frac{1}{2}=\frac{9}{4}x\frac{2}{3}\)
f \(Xx\frac{3}{5}-\frac{2}{5}=3\frac{3}{4}-1\)
bài 1: tìm x:
a) \(x\cdot\frac{7}{9}=\frac{2}{3}+2\frac{1}{2}\) b) \(\frac{5}{7}+x:\frac{9}{4}=\frac{4}{3}\)
Bài 2 : Tìm x , biết :
a , \(\frac{1}{2}xX-\frac{2}{3}+0,75=1,25X\frac{2}{3}\) b , 1 - \(\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\) c , (X+1) + (X+2) + (X+3) + (X+4) + ..... + (X+28) = 555
d, (X+4) + (x+6) + (X+8) + ... + (X+26) = 210
1.Tìm x, biết:
\(1+\)\(\frac{1}{3}+\frac{1}{6}+...+\frac{2}{Xx\left[x+1\right]}=1\frac{9}{11}\)
\(\frac{1}{1x3}+\frac{1}{3x5}+\frac{1}{5x7}+......+\frac{1}{Xx\left(X+2\right)}=\frac{8}{17}\)
Tìm x, biết x là số lẻ
bài 2:tìm x phân số
a)\(x:\frac{5}{4}=\frac{9}{5}+\frac{1}{2}=?\) b)\(\left(x+\frac{3}{4}\right)x\frac{5}{7}=?\frac{10}{9}\)
1.Tìm x, biết:a.frac{1}{2}xx+frac{2}{3}frac{5}{2}b.frac{x}{12}+frac{5}{24}frac{5}{6}c.(1234+x+766)x0,256,2:0,012.Tính bằng cách hợp lý.Afrac{1}{2}xfrac{5}{7}+frac{9}{7}x0,3+frac{1}{2}xfrac{4}{7}+frac{9}{4}+frac{9}{7}x0.2Bfrac{2002cdot15-1}{2001+2002cdot14}
Đọc tiếp
1.Tìm x, biết:
a.\(\frac{1}{2}\)x\(x\)+\(\frac{2}{3}\)=\(\frac{5}{2}\)
b.\(\frac{x}{12}\)+\(\frac{5}{24}\)=\(\frac{5}{6}\)
c.(1234+\(x\)+766)x0,25=6,2:0,01
2.Tính bằng cách hợp lý.
A=\(\frac{1}{2}\)x\(\frac{5}{7}\)+\(\frac{9}{7}\)x0,3+\(\frac{1}{2}\)x\(\frac{4}{7}\)+\(\frac{9}{4}\)+\(\frac{9}{7}\)x0.2
B=\(\frac{2002\cdot15-1}{2001+2002\cdot14}\)
1.Tìm x, biết:a.frac{1}{2}xx+frac{2}{3}frac{5}{2}b.frac{x}{12}+frac{5}{24}frac{5}{6}c.(1234+x+766)x0,256,2:0,012.Tính bằng cách hợp lý.Afrac{1}{2}xfrac{5}{7}+frac{9}{7}x0,3+frac{1}{2}xfrac{4}{7}+frac{9}{4}+frac{9}{7}x0.2Bfrac{2002cdot15-1}{2001+2002cdot14}
Đọc tiếp
1.Tìm x, biết:
a.\(\frac{1}{2}\)x\(x\)+\(\frac{2}{3}\)=\(\frac{5}{2}\)
b.\(\frac{x}{12}\)+\(\frac{5}{24}\)=\(\frac{5}{6}\)
c.(1234+\(x\)+766)x0,25=6,2:0,01
2.Tính bằng cách hợp lý.
A=\(\frac{1}{2}\)x\(\frac{5}{7}\)+\(\frac{9}{7}\)x0,3+\(\frac{1}{2}\)x\(\frac{4}{7}\)+\(\frac{9}{4}\)+\(\frac{9}{7}\)x0.2
B=\(\frac{2002\cdot15-1}{2001+2002\cdot14}\)
tìm x biết: \(2009-\left(4\frac{5}{9}+x-7\frac{7}{8}\right):15\frac{3}{2}=2008\)