Question

Tìm x biết: |x²+|x-1||=x²+2

ai giải nhanh nhất sẽ đc tick

Answer 1

Ta có:

x²\(\ge\)0

|x-1|\(\ge\)0

=>x²+|x-1|\(\ge\)0

=>|x²+|x-1||=x²+|x-1|

=>x²+|x-1|=x²+2

=>|x-1|=2

TH1: x-1\(\ge\)0

=>|x-1|=x-1

=>x-1=2

=>x=3

TH2: x-1<0

=>|x-1|=-x+1

=>-x+1=2

=>-x=1

=>x=-1

Vậy..............