Question

tìm x biết  ( x+1) + ( x+2) + ( x+3) +....+( x+100)=5750

Answer 1

(x+1)+(x+2)+(x+3)+...+(x+100)=5750

=> 100x + (1+2+3+...+100) = 5750

=> 100x + 5050                  = 5750

=> 100x                             = 5750 - 5050

=> 100x                             = 700

=> x                                  = 7

Answer 2

100x + ( 1+2+3+4+....+100)=5750

100x                                 =5750-5050

100x                                  =700

x                                      =7

Answer 3

Ta có: ( x+1) + (x+2) + (x+3) +...+ ( x+100) = 5750

<=> ( x + x + x + ...... + x ) + (1 + 2 + 3 + ..... + 100) = 5750

<=> 100x + 5050 = 5750

=> 100x = 5750 - 5050

=> 100x = 700

=> x = 700 : 100

=> x = 7

Answer 4

Ta có: ( x+1) + (x+2) + (x+3) +...+ ( x+100) = 5750

<=> ( x + x + x + ...... + x ) + (1 + 2 + 3 + ..... + 100) = 5750

<=> 100x + 5050 = 5750

=> 100x = 5750 - 5050

=> 100x = 700

=> x = 700 : 100

=> x = 7

Answer 5

Ta có: 

( x+1) + (x+2) + (x+3) +...+ ( x+100) = 5750

<=> ( x + x + x + ...... + x ) + (1 + 2 + 3 + ..... + 100) = 5750

<=> 100x + 5050 = 5750

=> 100x = 5750 - 5050

=> 100x = 700

=> x = 700 : 100

=> x = 7

Vậy x = 7

Answer 6

(x + 1 ) + ( x+  2 ) + ( x + 3 ) + ..... + ( x + 100 ) = 5750

( x + x + .... + x ) + ( 1 + 2 + 3 + .... + 100 )        = 5750

100x                   +               5050                        = 5750

100x                                                                    = 700

x                                                                          = 7