\(x-5\inƯ\left(19\right)\Leftrightarrow x-5\in\left\{-1;1;-19;19\right\}\Leftrightarrow x\in\left\{4;6;-14;24\right\}\)
Ta có : x - 5 \(\in\)Ư(19)
Ư(19) = { 1 ; 19 }
=> x = 1 + 5 = 6 ; 19 + 5 = 24
Ưoc(19)={1;19}
Suy ra : x-5 thuoc 19
x-5=19
x=19+5
x=24
\(x-5\inƯ\left(19\right)\)
\(\RightarrowƯ\left(19\right)=\left\{\pm1;\pm19\right\}\)
Ta có bảng :
x - 5 | 1 | -1 | 19 | -19 |
x | 6 | 4 | 24 | -14 |
\(\text{Vậy x }\in\left\{6;4;24;-14\right\}\)