\(\left(x-3\right)^2-\left(x+3\right)^2=24\)
\(\Leftrightarrow\left(x-3-x-3\right)\left(x-3+x+3\right)=24\)
\(\Leftrightarrow-6.\left(2x\right)=24\)
\(\Leftrightarrow-12x=24\)
\(\Leftrightarrow x=-2\)
Vậy ......
(x - 3)2 - (x + 3)2 = 24
\(\Rightarrow\) (x2 - 6x + 32) - (x2 + 6x + 32) = 24
\(\Rightarrow\) 0 - 12x = 24
\(\Rightarrow\) 12x = -24
\(\Rightarrow\) x = -2
\(\left(x-3\right)^2-\left(x+3\right)^2=24\)
\(\left(x-3+x+3\right)\left(x-3-x-3\right)=24\)
\(x^2-6=24\)
\(x^2=30\)
\(x=\sqrt{30}\)
