\(x=\frac{a}{b+c}=\frac{b}{c+a}=\frac{c}{a+b}\)
\(\text{Áp dụng t/c dãy tỉ số bằng nhau}\)
\(\Rightarrow\frac{a}{b+c}=\frac{b}{c+a}=\frac{c}{a+b}=\frac{a+b+c}{b+c+c+a+a+b}=\frac{a+b+c}{2b+2c+2a}=\frac{a+b+c}{2\left(a+b+c\right)}=\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{2}\)