+) Xét \(x\ge5\) có:
\(x-5-x=3\Leftrightarrow-5=3\) ( vô lí )
+) Xét x < 5 ta có:
\(5-x-x=3\Leftrightarrow5-2x=3\)
\(\Leftrightarrow2x=2\Leftrightarrow x=1\) ( t/m )
Vậy x = 1
Ta có :
\(\left|x-5\right|-x=3\)
\(\left|x-5\right|=3+x\)
\(\Rightarrow\left[{}\begin{matrix}x-5=3-x\\x-5=-\left(3-x\right)\end{matrix}\right.\)
TH1 : \(x-5=3-x\)
\(x+x=5+3\)
\(2x=8\)
\(\Rightarrow x=4\left(TM\right)\)
TH2 : \(x-5=-\left(3-x\right)\)
\(x-5=-3+x\)
\(x-x=5-3\)
\(x-x=2\) (vô lí)
Vậy \(x=4\) là giá trị cần tìm