\(\left(-\frac{2}{3}.x-\frac{3}{5}\right).\left(-\frac{3}{2}-\frac{10}{3}\right)=\frac{2}{5}\)
\(\Rightarrow\left(-\frac{2}{3}.x-\frac{3}{5}\right).\left(-\frac{29}{6}\right)=\frac{2}{5}\)
\(\Leftrightarrow-\frac{2}{3}.x-\frac{3}{5}=\frac{2}{5}:\left(-\frac{29}{6}\right)=-\frac{12}{145}\)
\(\Leftrightarrow-\frac{2}{3}.x=-\frac{12}{145}+\frac{3}{5}=\frac{15}{29}\)
\(\Leftrightarrow x=\frac{15}{29}:\left(-\frac{2}{3}\right)\)
\(\Leftrightarrow x=-\frac{45}{58}\)
\(\left(-\frac{2}{3}.x-\frac{3}{5}\right).\left(\frac{3}{-2}-\frac{10}{3}\right)=\frac{2}{5}\)
=> \(\left(-\frac{2}{3}.x-\frac{3}{5}\right).\left(-\frac{29}{6}\right)=\frac{2}{5}\)
=> \(\left(-\frac{2}{3}.x-\frac{3}{5}\right)=\frac{2}{5}:\left(-\frac{29}{6}\right)\)
=> \(-\frac{2}{3}.x-\frac{3}{5}=-\frac{12}{145}\)
=> \(-\frac{2}{3}.x=\left(-\frac{12}{145}\right)+\frac{3}{5}\)
=> \(-\frac{2}{3}.x=\frac{15}{29}\)
=> \(x=\frac{15}{29}:\left(-\frac{2}{3}\right)\)
=> \(x=-\frac{45}{58}\)
Vậy \(x=-\frac{45}{58}.\)
Chúc bạn học tốt!
