\(\frac{x}{12}=\frac{4}{3x-3}+\frac{1}{12}\)
\(\frac{x}{12}-\frac{1}{12}=\frac{4}{3\left(x-1\right)}\)
\(\frac{x-1}{12}=\frac{4}{3\left(x-1\right)}\)
=> ( x - 1 ) . 3 ( x - 1 ) = 48
=> ( x - 1 )2 . 3 = 48
=> ( x - 1 )2 = 16
Phần sau dễ bạn tự làm nốt nha
\(\frac{4}{3x-3}=\frac{4}{3\left(x-1\right)}\)
\(\Rightarrow\frac{x}{12}=\frac{4}{3\left(x-1\right)}+\frac{1}{12}=\frac{16}{12\left(x-1\right)}+\frac{x-1}{12\left(x-1\right)}=\frac{16+x-1}{12\left(x-1\right)}\)
\(\Rightarrow\)12x(x-1) = 12(16 + x - 1)
12x2 - 12x = 12.16 + 12x - 12
=> 12x2 = 192 + 24x - 12
=> 12x2 - 24x = 180
=>12x(x - 2) = 180
x(x - 2) = 65
Bạn làm nốt nhé, mình đang bận
