Question

Tim x biet \(\frac{x+1}{10}\)+\(\frac{x+1}{11}\)+\(\frac{x+1}{12}\)= \(\frac{x+1}{13}\)+\(\frac{x+1}{14}\)

 

Answer 1

\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)

\(\Leftrightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)

\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)

Mà \(\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)\ne0\)

\(\Rightarrow x+1=0\)

\(\Leftrightarrow x=0-1\)

\(\Leftrightarrow x=-1\)

Vậy \(x=-1\)

Answer 2

     x+1/10 + x+1/11 + x+1/12 = x+1/13 + x+1/14 = 0

<=> x+1/10 + x+1/11 + x+1/12 - x+1/13 - x+1/14 = 0

<=> (x+1)(1/10 + 1/11 + 1/12 - 1/13 - 1/14) = 0

Mà (1/10 + 1/11+ 1/12 - 1/13 - 1/14) khác 0

=> x+1 = 0

<=> x = 0-1

<=> x = -1

Vậy x = -1

Answer 3

x=1 k nha các bạn