Các câu hỏi tương tự
Tìm x, biết \(\frac{x-1}{2017}+\frac{x-3}{2015}+...+\frac{x-101}{1917}=\frac{x-103}{1915}+\frac{x-105}{1913}+...+\frac{x-203}{1815}\)
Tìm số hữu tỉ x biết:\(\frac{x-1}{105}+\frac{x-2}{104}-\frac{x-3}{103}=\frac{x-4}{102}+\frac{x-5}{101}-1\)
a)Tim x biet \(\frac{315-x}{101}+\frac{313-x}{103}+\frac{311-x}{105}+\frac{309-x}{107}+x\)=0
b) Tìm a,b thuộc Z biết (2a + 5b +1) . 2|3a +b| = 105
\(\frac{315-x}{101}+\frac{313-x}{103}-\frac{x-311}{105}-\frac{x-309}{107}=-4\)
tìm x
tìm x biết
\(\frac{315-x}{101}+\frac{313-x}{103}+\frac{311-x}{105}+\frac{309-x}{107}+4=0\)
Tìm x
\(\frac{315-x}{101}+\frac{313-x}{103}+\frac{311-x}{105}+\frac{309-x}{107}+4=0\)
Tim x
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
2/ tim x
\(\frac{x+2015}{5}+\frac{x+2016}{6}=\frac{x+2017}{7} +\frac{x+2018}{8}\)
3/ tim x
\(\frac{1}{3}+\frac{1}{6}+\frac{99}{101}+\frac{1}{15}+... +\frac{1}{x\left(2x+1\right)}=\frac{1}{10}\)
Tìm x thuộc Q biết:
\(\frac{315-x}{101}+\frac{313-x}{103}+\frac{311-x}{105}+\frac{309-x}{107}+4=0\)
giúp mình nha!
tìm x biết:
\(\frac{x-1}{99}-\frac{x+1}{101}+\frac{x-2}{98}-\frac{x+2}{102}+\frac{x-3}{97}-\frac{x+3}{103}+\frac{x-4}{96}-\frac{x+4}{104}=0\)