Các câu hỏi tương tự
tim x : \(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{47.49}=\frac{1}{x}\)
Cho \(\frac{1}{1.3}+\frac{1}{3.5}+....+\frac{1}{47.49}=\frac{1}{x}\). Tìm |x|
Tìm x thỏa mãn
a, \(\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{97.100}=|\frac{x}{3}|\)
b, \(\frac{4}{1.5}+\frac{4}{5.9}+...+\frac{4}{97.101}=|\frac{5x-4}{101}|\)
c,\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{100}\right)=|x-1\frac{99}{100}|\)
Tìm x, biết:
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x\left(x+3\right)}=\frac{125}{376}\)
Tìm x thuộc N, biết:
\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{x.\left(x+2\right)}=\frac{8}{17}\)
Tìm x nguyên biết: \(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{x\left(x+2\right)}=\frac{16}{34}\)
Tính
A =\(\frac{1}{2}\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2015.2017}\right)\)
B = 2x2-3x+5 với /x/ = \(\frac{1}{2}\)
C=15(y2x - x2y) với x-y=0
tìm x
a , \(\frac{1}{1.3}+\frac{1}{3.5}+.....+\frac{1}{x.\left(x+2\right)}=\frac{20}{41}\)
b , |x + 2016 | + | x + 2017 | +2018 = 3x
Tìm số tự nhiên x thoả mãn \(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{x.\left(x+2\right)}=\frac{16}{34}\)