a) |9-7x|>/0 suy ra
TH1: 9-7x=5-3x
ta có: 9-7x=5x-3
-5x-7x=-9-3
-12x=-12
x=1
TH2: 7x-9=5x-3
suy ra 7x-9=5x-3
7x-5x=9-3
2x=6
x=3
vậy x=3; x=1
a)|9-7x|=5x-3
=>|9-7x|\(\ge0\)
=>5x-3 \(\ge0\)
<=>9-7x=5x-3
=>7x+5x=9+3
(7+5)x=12
12x=12
x=1
<=>7x-9=5x-3
=>7x-5x=9-3
2x=6
x=3