b, \(4x^2-4x=-1\)
\(\left(2x\right)^2-4x+1=0\)
\(\left(2x\right)^2-2.2x.1+1^2\)
\(\left(2x-1\right)^2=0\)
\(\left(2x-1\right)^2=0^2\)
\(2x-1=0\)
\(2x=0+1\)
\(2x=1\)
\(x=1:2\)
\(x=\frac{1}{2}\)
b) \(4x^2-4x=-1\)
\(\Rightarrow\left(2x\right)^2-4x=-1\)
\(\Rightarrow\left(2x\right)^2-4x+1=0\)
\(\Rightarrow\left(2x\right)^2-2.2x+1^2=0\)
\(\Rightarrow\left(2x-1\right)^2=0\)
\(\Rightarrow2x-1=0\)
\(\Rightarrow2x=0+1\)
\(\Rightarrow2x=1\)
\(\Rightarrow x=1:2\)
\(\Rightarrow x=\frac{1}{2}.\)
Vậy \(x=\frac{1}{2}.\)
Chúc bạn học tốt!