Question

Tìm \(x\), biết :

a) 2(\(3x-2\))-3(\(x-2\))=-1

b) 2(\(3-3x^2\))\(\div3x\)(\(2x-1\))=9

hellp!!☹

Answer 1

\(2\left(3x-2\right)-3\left(x-2\right)=-1\)

\(6x-4-3x+6=-1\)

\(3x+2=-1\)

\(3x=-1-2\)

\(3x=-3\)

\(x=-1\)

\(2\left(3-3x^2\right):3x\left(2x-1\right)=9\)

\(6-6x^2:6x^2-3x=9\)

\(6-x^2-3x=9\)

\(-x^2-3x+6=9\)

\(-x^2-3x=5\)

\(-x\left(x+3\right)=5\)

\(x=-5;x=2\)