Tìm x:
1. ( 4x4 + 3x3 ) : ( -x3) + ( 15x2 + 6x ) : 3x = 0
2. ( 25x2 - 10x) : ( -5x) - 3( x-2) = 4
3. ( 42x3 - 12x ) : ( -6x) + 7x ( x+2) = 8
tìm x biết
x^3-6x^2+12x-8=-8
tìm x biết
x^3-6x^2+12x-8=-8
Tìm x biết: c/ x^3+6x^2+12x+8=0
Tìm x biết
a)(x+3)^2(x-2)^2=2x b)7x(x-2)=(x-2) c)8x^3-12x^2+6x-1=0
d)4x^2-9-x(2x-3)=0 e)x^3+5x^2+9x=-45 f)x^3-6x^2-x+30=0
(12x + 7)2(3x +2)(2x+1)=3
⇔ (12²x²+2.12.7x + 7²)(6x²+7x+2) = 3
⇔ [24.(6x² +7x +2) +1].(6x² +7x +2) =3
đặt: a= 6x² +7x +2
⇔ (24a+1).a = 3
⇔ (3a-1)(8a+3)=0
⇔ a=1/3 hoặc a=−3/8
chang pit lam nua??????????/
Tìm x , biết :
a. x(x - 2) - 7x + 14 = 0
b, x2(x - 3) + 12 - 4x = 0
c. x2 + 12x - 13 = 0
d. 4x2 - 4x = 8
e. x2 - 6x = 1
Tìm x , biết :
a. x(x - 2) - 7x + 14 = 0
b, x2(x - 3) + 12 - 4x = 0
c. x2 + 12x - 13 = 0
d. 4x2 - 4x = 8
e. x2 - 6x = 1
Tìm x , biết :
a. x(x - 2) - 7x + 14 = 0
b, x2(x - 3) + 12 - 4x = 0
c. x2 + 12x - 13 = 0
d. 4x2 - 4x = 8
e. x2 - 6x = 1