\(6+\frac{x}{33}=\frac{7}{11}\)
\(\Rightarrow\frac{x}{33}=\frac{7}{11}-6\)
\(\Rightarrow\frac{x}{33}=\frac{-59}{11}\)
\(\Rightarrow x=\frac{33.\left(-59\right)}{11}\)
\(\Rightarrow x=-177\)
Vậy x = -177
_Chúc bạn học tốt_
6 + \(\frac{x}{33}\) = \(\frac{7}{11}\)
\(\frac{x}{33}\)= \(\frac{7}{11}\)- 6
\(\frac{x}{33}\)= \(-\frac{59}{11}\)
\(\frac{x}{33}\)= \(-\frac{177}{33}\)
\(x\) = \(-177\)