Có (5x-1+7y-6)/(3+5)=(5x+7y-7)/4x
(5x+7y-7)/8=(5x+7y-7)/4x
=> 8=4x
=> x=2
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Tìm x, biết:\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-7y-7}{4x}\)
tìm x,y biết : \(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-7y-7}{4x}\)
Tìm x, y biết :
\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x+7y}{4x}\)= 7
Tim x ; y biet: (5x-1)/3 = (7y-6)/5 = (5x-7y-7)/4x
\(\frac{5x-1}{3}\)= \(\frac{7y-6}{5}\)= \(\frac{5x-7y-7}{4x}\).Tìm x,y
tim x;y
\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x+7y-7}{4x}\)
\(\frac{5x-1}{3}\)= \(\frac{7y-6}{5}\)= \(\frac{5x+7y-7}{4x}\)
Tìm x,y,z
tìm x;y\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+1}\)=0
\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{6x+7y-7}{4x}\)
tìm x,y biết:
a \(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
b \(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x+7y-7}{4x}\)
c \(\left|x+5\right|+\left(3y-4\right)^{2010}=0\)