\(4^3x+1=64\)
\(\Leftrightarrow64x=63\)
\(\Leftrightarrow x=\frac{63}{64}\)
Vậy \(x=\frac{63}{64}\)
43x + 1 = 64
=> 43x + 1= 43
=> 3x + 1 = 3
=> 3x =2
=> x =2/3
Nếu đề là \(4^{3x+1}=64\)
\(\Leftrightarrow4^{3x+1}=4^3\)
\(\Leftrightarrow3x+1=3\Leftrightarrow3x=2\)
\(\Leftrightarrow x=\frac{2}{3}\)
\(4^{3x+1}=64\)
\(\Rightarrow4^{3x+1}=4^3\)
\(\Rightarrow3x+1=3\)
\(\Rightarrow3x=2\)
\(\Rightarrow x=\frac{2}{3}\)
Vậy....................
HOK TỐT
\(4^{3x+1}=64\)
\(4^{3x+1}=4^4\)
\(\Rightarrow4^{3x+1}=4^3\)
\(\Rightarrow3x+1=3\)
\(\Rightarrow3x=2\)
\(\Rightarrow x=\frac{2}{3}\)
Học tốt nha!!!
