\(3^x+3^{x+1}+3^{x+2}=117\)
\(3^x+3^x.3+3^x.9=117\)
\(3^x\left(1+3+9\right)=117\)
\(3^x.13=117\)
\(3^x=117:13\)
\(3^x=9\)
\(3^x=3^2\)
\(x=2\)
Vậy \(x=2\)
(3^x)+(3^x+1)+(3^x+2)=117
(3^x).(1+3+9)=117
3^x=117:13
3^x=9
3^x=3^2
=>x=2
chúc bạn học tốt nha