\(3x-\left(15-x\right)=17+x\)
\(\Rightarrow3x-15+x=17+x\)
\(\Rightarrow3x+x-x=17+15\)
\(\Rightarrow3x=32\)
\(\Rightarrow x=\frac{32}{3}\)
trả lời:
3x-(15-x)=17+x
(=)3x-15+x=17+x
(=)3x+x-x=17+15
(=)3x=32
(=)x=\(\frac{32}{3}\)
Ta có : 3x + ( 15 - x ) = 17 + x .
=> 3x - 15 + x = 17 + x .
=> 3x + x - x = 17 + 15 .
=> 4x = 32 .
=> x = 32 : 4 .
=> x = 8 .
Vậy x = 8 .
3x - ( 15 - x ) = 17 + x
3x - 15 + x = 17 + x
4x - 15 = 17 + x
4x - x = 17 + 15
3x = 32
x = 32/3
2x - (15 - x) = 17 + x
4x - 15 = 17 + x
4x = 17 + x + 15
4x = x + 32
4 = x + 32 - x
3x = 32
x = 32 : 3
x = 32/3
