399 : (2x - 1) = 397
=> 2x - 1 = 9
2x = 10
x = 5
\(3^{99}:\left(2x-1\right)=3^{97}\)
\(\Rightarrow2x-1=3^{99}:3^{97}\)
\(\Rightarrow2x-1=3^2=9\)
\(\Rightarrow2x=9+1=10\)
\(\Rightarrow x=5\)
399 : (2x - 1) = 397
=> 2x - 1 = 9
2x = 10
x = 5
\(3^{99}:\left(2x-1\right)=3^{97}\)
\(\Rightarrow2x-1=3^{99}:3^{97}\)
\(\Rightarrow2x-1=3^2=9\)
\(\Rightarrow2x=9+1=10\)
\(\Rightarrow x=5\)
tim X biet
3^99 : (2.x-1)^3 = 3^97
Tim x
x+1/99+x+2/98+x+3/97+x+4/96=-4
tim x cua N biet 1+3+5+..............................................+99= (x-2)^2
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
tim x
tinh : 1+2-3+4+5+6+7+8+9+...+97+98-99
tim x: 1-|x+1|=-7
tim x biet N thuoc
a) 2-(x+3)=1+2+3+4+5+..............+99
b)(x+1)+(x+2)+(x+3)+(x+4)+...............+(x+100)=5750
giup mk nha cac ban , mk dang can gap lam
Tìm x bt:
a) x-1/99 + x-2/98 + x-3/97 + x-4/96 = 4
b) x+1/99 + x+2/98 + x+3/97 = 3
c) x-1/99 + x-2/49 + x-4/32 = 6
Giúp mik với! Th5 mik mới nộp nhưng mong các bn giúp mik!
Tim x thuoc N biet
a)13 + 23 + 33 + ...+103 = (x +1)2
b)1+3+5+...+99=(x - 2)2
giúp với ạ:
bài 1: tính tổng các số nguyên biết:
1) -20 < x < 21
2) -18 ≤ x ≤ 17
3) -27 < x ≤ 27
4) /x/ ≤ 3
5) /-x/ < 5
bài 2: tính tổng:
1) 1 + (-2) +3+(-4)+....+19+(-20)
2) 1-2+3-4+....+99-100
3) 2-4+6-8+....+48-50
4) -1+3-5+7-...+97-99
5) 1+2-3-4+...+97+98-99-100