=> [3x-7/9]^3= -8/27
=> 3x -7/9 = -2/3 => 3x = 1/9=> x= 1/27
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=> [3x-7/9]^3= -8/27
=> 3x -7/9 = -2/3 => 3x = 1/9=> x= 1/27
đúng cái nhé
Tim x biet
c) (x - 2)(x + 3)>0
d) \(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
Tìm x biet:
a,93/17:x+(-21/17):x+22/7:22/3=5/14
b,-32/27-(3x-7/9)^3=-24/27
c,[(3,75:1/4)+12/5.125%)-(7/2.0,8-1,2:3/2)]:(3/2+0,75)x=64
-32/27-(3x-7/90) mũ 3 = -24/27
\(\left(\frac{-32}{27}\right)-\left(3x-\frac{7}{9}\right)^3=\frac{-24}{27}\)
bai 1:tim x
a) (x+1/5)2+17/25=26/25
b)-1va 5/27-(3x-7/9)3=-24/27
bai 2:cho A=n+2/n-5 (n thuoc Z ;n khac 5).Tim x de A thuoc Z
-1 5/27 - (3x-7/9)^3 = -24/27
-1 5/27-(3x-7/9)^3=-24/27
giúp mình với
-1 5/27-(3x-7/9)mũ 3=-24/27
-32/27-(3.x-7/9)3=-24/27
cac banlam nhanh nha minh can gap
dau cham la dau nhan nhe