Tìm x biết: 3. (4 – x) – 2. ( x- 1) = x + 20
12 - 3x - 2x + 2 = x + 20
-5x + 14 = x + 20
-5x + 14 - x - 20 =0
-6x - 6 = 0
-6x = 6
x = -1
3. (4 – x) – 2. ( x- 1) = x + 20
\(=>12-3x-2x+2=x+20\)
\(=>14-5x-x-20=0\)
\(=>-6-6x=0=>-6\left(1+x\right)=0=>1+x=0=>x=-1\)
Vậy x= - 1
Hok tốt nha !
=> 12-3x-2x+2=x+20
=> 5x=-6
=> x=-6/5
vậy x=-6/5
\(12-3x-2x+2=x+20\)
\(-5x+14=x+20\)
\(-5+14-x-20=0\)
\(-6x-6=0\)
\(-6x=0+6\)
\(-6x=6\)
\(=>x=-1\)
<=> 12 - 3x - 2x + 2 = x + 20
<=> 12 - 5x + 2 = x + 20
<=> 12 + 2 -20 = x + 5x
<=> - 6 = 6x
=> x = -1
Vậy x = -1
HOK TỐT
\(3.\left(4-x\right)-2.\left(x-1\right)=x+20\)
\(\Leftrightarrow12-3x-2x+2=x+20\)
\(\Leftrightarrow\left(12+2\right)-\left(3x+2x\right)=x+20\)
\(\Leftrightarrow14-5x=x+20\)
\(\Leftrightarrow-5x-x=20-14\)
\(\Leftrightarrow-6x=6\)
\(\Leftrightarrow x=6:\left(-6\right)\)
\(\Leftrightarrow x=-1\)
Vậy : \(x=-1\)
Rất vui vì giúp đc bạn !!!
3.(4 - x) - 2.(x - 1) = x + 20
=> 12 - 3x - 2x + 2 = x + 20
=> - 3x - 2x - x = 20 - 12 - 2
=> - 6x = 6
=> x = -1
Hok tốt
\(3\cdot\left(4-x\right)-2\cdot\left(x-1\right)=x+20\)
\(\Rightarrow12-3x-2x+2=x+20\)
\(\Rightarrow14-5x=x+20\)
\(\Rightarrow-5x-x=-14+20\)
\(\Rightarrow-6x=6\)
\(\Rightarrow x=\frac{6}{-6}=-1\)
Vậy x=-1
\(12-3x-2x+2=x+20\)
\(12-3x-2x+2=x+20\)
\(-5x+14=x+20\)
\(\Rightarrow-5x+14-x-20=0\)
\(-6x-6=0\)
\(-6x=6\)
\(x=-1\)